Simple Beam -Triangle Load-
Sunday 21st of June 2026 07:16:33 AM
Laterally Braced
Steel Beam
Shape:
A(in2)= 0 d(in)= 0
b(in)= 0 Wt(lb/ft)= 0
Sx(in3)= 0 Sy(in3)= 0
Ix(in4)= 0 Iy(in4)= 0
Input Data
Span L(ft):
ws(k/ft):
Fy(ksi):
E(ksi):
φb:
Results
Shape: 
Section Modulus
Req. Sx(in3)= 0
Check=  
Deflection Criteria
MaxDef@x_(in)=
x dist(ft)=
L/360(in)=
L/240(in)=
ASD Design:
we= Service loads (unfactored),(k/ft),-- Not included Beam self weight
Common Values: Fy=36 ksi, E=29,000 Ksi,
φb=0.60   (=1/1.67 AISC  Table 3-2)
Analysis
w=0 k/ft
R1=0 k R2=0 K
M=0 k-in x;=0 in AISC 13th_Ed Table 3-23
Δc;=0 in AISC 13th_Ed Table 3-23
Δc240;=0 in Δc360;=0 in
Sreq=0 (in3)
Check Sx=